Saved Bookmarks
| 1. |
In A.C. circuit, when E = E_0 sin omegat supply applied, current is obtained in circuitI=I_0 sin (omegat-pi/2) , so power consumed is circuit will be …… |
|
Answer» <P>`P=(E_0I_0)/SQRT2` `therefore` Real power `P = E_"RMS" I_"rms" cosdelta` `=E_(rms)I_(rms)xx "cos"pi/2` `=E I xx 0 [ because E_(rms) = E, I_(rms)=I]` `therefore` P=0 |
|