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In a car lift, a force F, acts on a smaller piston ofradius 5 cm. The radius of the larger piston is15 cm. Mass of the car to be lifted up is 1350 kgCalculate the minimum value of F. (3 marks) |
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Answer» According to Pascal's law, Pressure is transmitted equally and undiminished through out the fluid.P1=P2F1/A1=F2/A2F1= (A1/A2 ) F2=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)=1470N=1.5 x 10³ NThe air pressure that will produce this forceP=F1/A1=1.5x10³N/π(5x10⁻²)² m=1.9 x 10⁵ PaThis is almost the double of atmospheric pressure. |
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