1.

In a car lift, a force F, acts on a smaller piston ofradius 5 cm. The radius of the larger piston is15 cm. Mass of the car to be lifted up is 1350 kgCalculate the minimum value of F. (3 marks)

Answer»

According to Pascal's law, Pressure is transmitted equally and undiminished through out the fluid.P1=P2F1/A1=F2/A2F1= (A1/A2 ) F2=[π(5 x10⁻²m)²/π(15x10⁻²m)² ](1350Nx9.8m/s2)=1470N=1.5 x 10³ NThe air pressure that will produce this forceP=F1/A1=1.5x10³N/π(5x10⁻²)² m=1.9 x 10⁵ PaThis is almost the double of atmospheric pressure.



Discussion

No Comment Found

Related InterviewSolutions