InterviewSolution
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InterviewSolution
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In a certain polytropic process the volume of argon was increased `alpha= 4.0` times. Simultaneously, the pressure decreased `beta = 8.0` times. Find the molar heat capacity of argon in this process. Assuming the gas to be ideal. |
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Answer» Let the process be polytropic according to the law `pV^n = constant` Thus, `p_f V_f^n = p_i V_i^n` or, `((p_i)/(p_f)) = beta` So, `alpha^n = beta` or `1n beta = n 1n alpha` or `n = (1n beta)/(1 n alpha)` In the polytropic process molar heat capacity is given by `C_n (R(n - gamma))/((n - 1)(gamma - 1)) = (R)/(gamma - 1) -(R)/(n - 1)` =`(R)/(gamma - 1) = (R 1n alpha)/(1 n beta - 1n alpha)`, where `n = (1 nbeta)/(1n alpha)` So, `C_n = (8.314)/(1.66 0-1)-(8.314 1n 4)/(1 n 8 - 1n 4) = -42 J//mol.K`. |
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