1.

In a certain reaction 2A + B hArr 4C, the concentration of A decreases from 5 xx 10^(-3) " mol"//L to 2 xx10^(-3) " mol"//L in 30 s. What is the rate with respect to C ?

Answer»

`5XX10^(-5) " mole " L^(-1)s^(-1)`
`5xx10^(-5) L^(-1) " mole"^(-1) s^(-1)`
`21 xx10^(-4) " mole" L^(-1)s^(-1)`
`2 xx 10^(-4) L^(-1) " mole"^(-1) s^(-1)`

Solution :The rate of reaction with respect to
`A=("Change in concentration")/("TIME")`
`(d[A])/(dt)=(5xx10^(-3)-2xx10^(-3))/(30)=(3xx10^(-3))/(30)`
`=1xx10^(-4) " mol" // "lit's`
reaction is `2A+B to 4C`
`(1)/(2)(d[A])/(dt)=(1)/(4)(d[C])/(dt)`
The rate of reaction in terms of 'C' is
`(Delta[C])/(Delta t)=(4)/(2)xx(Delta[A])/(Delta t)`
`=2xx(d[A])/(dt)=2xx1xx10^(-4)=2xx10^(-4) " mole " // L^(-1)` .SEC


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