InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
In a chamber, a uniform magnetic field of 6.5G ( 1G = 10^(-4) T) is . Maintained . An electron is shot into field witha speed of 4.8 xx 10^(6) ms^(-1) normal to the field . Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.6 xx 10^(-19) C, m = 9.1 xx 10^(-31) kg) |
|
Answer» Solution :`B=6.5 XX 10^(-4) T,v= 4.8 xx 10^(6) ms ^(-1)` `BQV = (MV^2)/(r) , r = (mV)/(QB)= (9.1 xx 10^(-31) xx 4.8 xx 10^6)/(1.6 xx 10^(-19) xx 6.5 xx 10^(-4)) = 4.2 xx 10^(-2) m = 4.2 cm ` |
|