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In a chamber, a uniform magnetic field of 6.5G ( 1G = 10^(-4) T) is . Maintained . An electron is shot into field witha speed of 4.8 xx 10^(6) ms^(-1) normal to the field . Explain why the path of the electron is a circle. Determine the radius of the circular orbit. (e = 1.6 xx 10^(-19) C, m = 9.1 xx 10^(-31) kg) |
| Answer» <html><body><p></p>Solution :`B=6.5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-4) T,v= 4.8 xx 10^(6) ms ^(-1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/bqv-3563546" style="font-weight:bold;" target="_blank" title="Click to know more about BQV">BQV</a> = (<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(r) , r = (mV)/(<a href="https://interviewquestions.tuteehub.com/tag/qb-610265" style="font-weight:bold;" target="_blank" title="Click to know more about QB">QB</a>)= (9.1 xx 10^(-31) xx 4.8 xx 10^6)/(1.6 xx 10^(-19) xx 6.5 xx 10^(-4)) = 4.2 xx 10^(-2) m = 4.2 cm `</body></html> | |