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In a chemical equilibrium `A + B hArr` C + D, when one mole each of the two reactants are mixed, `0.6` mole each of the products are formed. The equilibrium constant calculated isA. 1B. `0.36`C. `2.25`D. `4//9` |
Answer» Correct Answer - C `{:(,A,+,B,hArr,C,+,D),("Initial",1,,1,,0,,0),("Remaining at equiibrium",0.4,0.4,0.4,,0.6,,0.6):}` `K = ([C][D])/([A][B]) = (0.6xx0.6)/(0.4xx0.4) = (36)/(16) = 2.25` |
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