1.

In a chemical equilibrium, the rate constant for the backward reaction is `7.5xx10^(-4)` and the equilibrium constant is `1.5` the rate constant for the forward reaction is:A. `2xx10^(-3)`B. `5xx10^(-4)`C. `1.12xx10^(-3)`D. `9.0xx10^(-4)`

Answer» Correct Answer - C
`K = (r_(f))/(r_(b)) implies 1.5 = (r_(f))/(7.5xx10^(-4)) implies r_(f) = 1.12xx10^(-3)`


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