In a chemical reaction DeltaH is 150 k J and DeltaS is 100 J K^(-1) at – InterviewSolution

1.	In a chemical reaction DeltaH is 150 k J and DeltaS is 100 J K^(-1) at 300 K, then DeltaG is
Answer» 200 K J 333 k J 300 k J 120 k J Solution :`DeltaG=DeltaH-TDeltaS` `=150-300(100xx10^(-3))=150-30=120 KJ`.

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