1.

In a chemical reaction, the rate constant for the backward reaction is 7.5xx10^(-4) and the equilibrium constant is 1.5.The rate constant for the forward reaction is :

Answer»

`5xx10^(-4)`
`2xx10^(-3)`
`1.125xx10^(-3)`
`9.0xx10^(-4)`

SOLUTION :`K=(k_(F))/(k_(b))`
or `k_(f)=K xx k_(b)`
`=1.5xx7.5xx10^(-4)`
`=1.125xx10^(-3)`


Discussion

No Comment Found

Related InterviewSolutions