1.

In a circuit potential difference across resistence `V = (4 +- 0.25)V `and curent in resistence ,`f = (1 +- 0.1)` what is the value of resistence with its percentage errorA. `(4 +- 0.4)Omega`B. `4 Omega + 16.25%`C. `4 Omega + 18.25%`D. `4 Omega + 22.25%`

Answer» Correct Answer - b
`E_(0) = (V_(0))/(I_(0)) = (4)/(1) = 4 Omega`
`(DeltaR)/(R ) = (Delta V)/(V) + (Delta I)/(I)`
`= (0.25)/(4) + (0.1)/(1.0) = 0.1625`
`R = 4Omega + 16.25%`


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