1.

In a circuit, the value of the alternating current is measured by hot wire ammeter as 10 ampere. What will be its peak value ?

Answer»

`10 A`
`20 A`
`14.14 A`
`7.07 A`

SOLUTION :`I_(rms)=I_m/sqrt2`
`THEREFORE I_m=sqrt2xxI_(rms)`
=1.414 X 10
=14.14 A


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