Saved Bookmarks
| 1. |
In a circular parallel plate capacitor radius of each plate is 5 cm and they are separated by a distance of 2mm. Calculate the capacitance and the energy stored. When it is charged by connectig battery of 200 V. (given epsilon_(0) = 8.854 xx 10^(-12) Fm^(-1)) |
|
Answer» SOLUTION :Radius `r = 5 cm = 5 xx 10^(-2)m` `d = 2 xx 10^(-3)m` : voltage applied = 200 V `epsilon_(0) = 8.8754 xx 10^(-12) Fm^(-1)` `A = pi r^(2) = 3.142 xx (5 xx 10^(-2))^(2) = 0.007855 m^(2)` `C = (epsilon_(0)A)/(d)` `C = (8.854 xx 10^(-12) xx 0.007855)/(2 xx 10^(-3)) = 34.8 xx 10^(-12)F` `U = (1)/(2)C V^(2)` `U = (1)/(2) xx 34.8 xx 10^(-12)xx(200)^(2) = 6.96 xx 10^(-7)J` |
|