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In a class 10 boys are more than the girls. from this form an equation and draw a graph for this. |
| Answer» LET number of boys be x.Number of girls be y.Given that total number of student is 10 so thatx+y=10Subtract y both SIDE we getx=10–yPlug y=0,5,10 we getx=10–0=10x=10–5=5x=10–10=0Therefore, the required points are (0,10),(5,5),(10,0).Given that If the number of girls is 4 more than the number of boysSo thaty=x+4Plug x=−4,0,4, and we gety=−4+4=0y=0+4=4y=4+4=8Therefore, the required points are (−4,0),(0,4),(4,8).Since the point of INTERSECTION in the above graph is (3,7), Therefore, the number of boys is 3 and the number of girls is 7.Step-by-step explanation:HOPE THIS HELPS PLEASE MARK AS BRAINLIEST. | |