1.

In a class of 50 boys, 35 boys play carom and 20 boys play chess then the number of boys play both games is (1) 5 (2) 30 (3) 15(4) 10

Answer»

(1) 5 

n(A ∪ B) = n(A) + n(B) – n(A n B) ⇒ 50 = 35 + 20 – n(A ∩ B) ⇒ n(A ∩ B) = 5



Discussion

No Comment Found