1.

In a class of 50 students, it was found that 30 students read "Hitavad", 35 students read "Hindustan" and 10 read neither. How many students read both "Hitavad" and "Hindustan" newpapers?1. 252. 353. 154. 305. None of the above/More than one of the above

Answer» Correct Answer - Option 1 : 25

Concept:

Let A and B denote two sets of elements.

  • n(A) and n(B) are the numbers of elements present in set A and B respectively.
  • n(A ⋃ B) is the total number of elements present in either set A or B.
  • n(A ⋂ B) is the number of elements present in both sets A and B.
  • n(A ⋃ B) = n(A) + n(B) - n(A ⋂ B)

 

Calculations:

Let A be the set of students who read "Hitavad" and B the set of students who read "Hindustan".

From the given information:

n(A ⋃ B) = 50 - 10 = 40.

n(A) = 30.

n(B) = 35.

By using n(A ⋃ B) = n(A) + n(B) - n(A ⋂ B), we get:

40 = 30 + 35 - n(A ⋂ B)

⇒ n(A ⋂ B) = 25.

∴ The number of students who read both "Hitavad" and "Hindustan" newspapers is n(A ⋂ B) = 25.



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