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. In a clean drive, the garbage collected by 11 cubical containers of side 20 cm is to be emptied into cylindrical tanks of radius 2 m and height 3.5 m daily. In how many days will tank will be filled completely.. |
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Answer» In 500 DAYS tank will be filled completely. Step-by-step explanation:Given that:Total number of CUBICAL containers = 11 containersLength of each side of container = 20 cmFormula to find the volume of a CUBE:Volume of cube = (edge)³ cubic unit. Finding the volume of one cubical container:→ Volume of one cubical container = (20)³ cm³→ Volume of one cubical container = 8000 cm³Finding the volume of 11 cubical containers:→ Volume of 11 cubical container = 8000 × 11 cm³→ Volume of 11 cubical container = 88000 cm³Given that:Radius of cylindrical tank = 2 mHeight of cylindrical tank = 3.5 mFormula to find the volume of cylinder:Volume of cylinder = πr²h cubic unitWhere, r = Radius of cylinder h = Height of cylinder π = 22/7Finding the volume of cylindrical tank:→ Volume of cylindrical tank = π × 2² × 3.5 m³→ Volume of cylindrical tank = (22 × 4 × 35)/(7 × 10) m³→ Volume of cylindrical tank = 44 m³Converting the 44 m³ into cm³:1 m³ = 1000000 cm³44 m³ = 44000000 cm³To find:In how many days will tank will be filled completely.Finding the number of days taken by 11 cubical containers to completely filled the cylindrical tank:→ Number of days = (Volume of cylindrical tank) / (Volume of 11 cubical containers) → Number of days = (44000000 cm³) / (88000 cm³) → Number of days = 500 days. |
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