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In a clock, what is the time period of meeting of the minute hand and the second hand ?A. `59s`B. `(60)/(59)s`C. `(59)/(60)s`D. `(3600)/(59)s`

Answer» Correct Answer - D
`omega_(1)t-omega_(2)t=2pi`
:. `t=(2pi)/(omega_(1)-omega_(2))`
`=(2pi)/((2pi//T_(1))-(2pi//T_(2)))`
`=(T_(1)T_(2))/(T_(2)-T_(1))`
`=((3600)(60))/((3600)-(60))`
`=(3600)/(59)s`


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