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In a cogulation experiment, 5 mL of As_(2)S_(3) is mixed with 0.1 M solution of electrolyte AB so that the thtal volume is 10 mL. It was found that all solution coagulates leaving AB equivaalent of 0.1 mL of 0.1 M in the solution. Calculate the flocculation value of AB for As_(2)S_(3) sol. |
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Answer» Solution :Amount of `0.1` M AB solution ADDED `=(10-5)mL =5 mL` 0.1 M AB left behind in the solution `=0.1 mL` `therefore0.1` M AB used up for coagulation `=5-0.4 =4.6 mL` `4.6 mL` of 0.1 M AB CONTAINS `AB=(4.6)/(1000)xxx0.1` mole `=0.46` millimole At thtal volume of the SOL after mixing with electrolyte solution is 10 mL, amount of AB required for coagulation of 1 L, i.e., 1000 mL of the sol = 46 milimiles. `therefore` Flocculation VALUE `=46.` |
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