1.

In a common - base circuit of transistor , current amplification factor is 0.95 Calculate the emitter current , if base current is 0.2 mA :

Answer»

4 mA
0.4 mA
2.1 A
0.21 A

Solution :Here , `0.95=I_c/I_e" or " I_c=0.95I_e`
`I_e = 0.2 xx10^(-3) + 0.95 I_e " or "0.05I_e = 0.2 xx10^(-3)`
`:. I_e = (0.2 )/(0.05 ) XX 10^(-3) = 4 xx10^(-3) A`


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