1.

In a common emitter amplifier output resistance is 2000 ohm and input resistance is 5000 ohm. The input signal is of 10 mV and beta=50, Then output voltage is

Answer»

1.25 V
2.25 V
2.50 V
3.0V

Solution :INPUT voltage `Deltav_i = 10mV = 10^(-2)V`
`R_i=2000Omega`
`Deltai_b=(Deltav_i)/(R_i)=15^2/2000=5xx10^(-6)A`
`beta = (Deltai_c)/(Deltai_b)`
Then `Delta_(IC)=beta Delta_(ib)= 2.5 xx10^(-4)A`
Then OUTPUT voltage
`DeltaV_0=DeltaI_c XX R_0 = 1.25 V`


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