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In a common emitter amplifier output resistance is 5000 ohm and input resistance is 2000 ohm. If peak value of signal voltage is 10 mVand beta = 50 , then the peak value of output voltage is : |
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Answer» `5xx 10^(-6)` VOLT Hence `A_v = beta xx R_0//R_i=50xx5000//2000=125` `DeltaV_e=A_vxx DeltaV_b=125xx10mV = 125 V` |
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