1.

In a common emitter amplifier output resistance is 5000 ohm and input resistance is 2000 ohm. If peak value of signal voltage is 10 mVand beta = 50 , then the peak value of output voltage is :

Answer»

`5xx 10^(-6)` VOLT
`2.5 xx10^(-4)` volt
1.25 volt
125 volt

Solution :`R_0=500 Omega , R_i=2000 Omega , BETA = 50`
Hence `A_v = beta xx R_0//R_i=50xx5000//2000=125`
`DeltaV_e=A_vxx DeltaV_b=125xx10mV = 125 V`


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