1.

In a compound A_(x)B_(y)

Answer»

MOLES of A = moles of B = moles of `A_(X)B_(y)`
EQ.of A = eq of B = eq.of `A_(x)B_(y)`
y `XX ` moles of A = y `xx` moles of B = `(x+y) xx` moles of `A_(x)B_(y)`
y `xx` moles of A = y `xx` moles of B

Answer :d


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