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In a compound microscope, both the objective and eyepiece are of short focal lengths. Why? |
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Answer» Solution :The magnifying POWER of compound microscope is `m=L/(f_o) (1+D/f_e) Lto`length of microscope TUBE m will be GREATER if the FOCAL LENGTHS of objective `f_0` and that of eyepiece `f_e` are short. |
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