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In a compound microscope, the object is 1 cm from the objective lens. The lenses are 30 cm apart and the intermediate image is 5 cm from the eye-piece. What magnification is produced? |
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Answer» Solution :As the lenses are 30cm apart and intermediate IMAGE is formed 5 cm in front of eye lens, `u_(E)=5cmandv=L-u_(e)=30-5=25cm` Now as in case of compound MICROSCOPE, `MP=mxxm_(theta)=-v/uxx[D/u_(e)]` Here u = 1 cm and D = 25 cm So, `MP=-25/1xx[25/5]=-125` Negative sign implies that final image is inverted. |
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