1.

In a compound, nitrogen atoms (N) make cubic close packed lattice and metal atoms (M) occupy one third of the tetrahedral voids present. Determine the formula of the compound formed by M and N.

Answer»

SOLUTION :LET the number of nitrogen atoms (N) be `= x`
Then number of TETRAHEDRAL voids `= 2X`
and number of metal atoms = `(2)/(3)x`
`"Ratio of "N: M = x : (2)/(3)x=1(2)/(3)`.
Or`"Ratio of "M: N = (2)/(3):1`
`therefore` The FORMULA of the compound is `M_(2)N_(3)`.


Discussion

No Comment Found