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In a convex hexagon two diagonals are drawn at random. The probability that the diagonals intersect at an interior point of the hexagon isA. `5//12`B. `7//12`C. `2//5`D. none of these |
Answer» Correct Answer - A We have, Number of diagonals of a hexagon `- .^(6)C_(2)-6=9` Number of ways of selecting two diagonals `= .^(9)C_(2)=36` Number of ways of selecting two intersecting diagonals = Number of ways of selecting four vertices of the hexagon `=.^(6)C_(4)=15` Hence, required probability `=(15)/(36)=(5)/(12)` |
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