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In a cricket match, a batsman hits a boundary 6 times out of 3 balls he plays. Find the probability that he did not hit a boundary. |
Answer» It is given that Number of times boundary was hit = 6 Total number of balls played = 30 So we get Number of times boundary was not hit = 30 – 6 = 24 We know that Probability that the batsman did not hit a boundary = number of times boundary was not hit/ total number of balls played By substituting the values Probability that the batsman did not hit a boundary = 24/30 By division Probability that the batsman did not hit a boundary = 4/5 = 0.8 |
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