1.

In a cubic crystal of CsCl (density = 3.97 gm//cm^(3)) the eight corners are occupied by Cl^(–) ions with Cs+ ions at the centre. Calculate the distance between the neighbouring Cs^(+) and Cl^(–) ions.

Answer»

Solution :`3.94=(1XX(M)/(N_(A)))/(a^(3))=(168.5)/(6.022xx10xxa^(3))`
`impliesa^(3)=(168.5)/(6.022xx10^(-23)xx3.97)`
`a^(3)=7.05xx10^(-23)CM^(3)`
`a=4.13xx10^(-8)` cm
`r_(+)+r_(-)=(asqrt(3))/(2)=3.577xx10^(-8)`
3.577xx10^(-10) cm`
=3.577 Å


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