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In a cubic type unit cell, A atoms are at one half faces, while B atoms are at the corners of the cube. Calculate the formula of the compound. |
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Answer» SOLUTION :NUMBER of atoms of A : (3 faces, `1/2` fraction), i.e., `3 xx 1/2=3/2` Number of atoms of B : (8 corners, `1/8` fraction), i.e., `8 xx 1/8 =1` So, the formula of the compound = `A_(3//2) B = A_3B_2` |
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