In a cubical box of volume V, there are N molecules of a gas moving randomly. If m is mss of ech molecule and`V^(2)` is the meansquare of x component of the velocity of molecules, then the pressure of the gas is-A. `P = 1/3(mNv^2)/(V)`B. `P=(mNv^2)/(V)`C.D. `P=mNv^2`

In a cubical box of volume V, there are N molecules of a gas moving ra

1.	In a cubical box of volume V, there are N molecules of a gas moving randomly. If m is mss of ech molecule and`V^(2)` is the meansquare of x component of the velocity of molecules, then the pressure of the gas is-A. `P = 1/3(mNv^2)/(V)`B. `P=(mNv^2)/(V)`C.D. `P=mNv^2`
Answer» Correct Answer - B refer to derivation (asked only x - compnent)

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In a cubical box of volume V, there are N molecules of a gas moving randomly. If m is mss of ech molecule and`V^(2)` is the meansquare of x component of the velocity of molecules, then the pressure of the gas is-A. `P = 1/3(mNv^2)/(V)`B. `P=(mNv^2)/(V)`C.D. `P=mNv^2`

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