1.

In a cyclic quadrilateral PQRS angle P=(2x+4)° , angle Q=(y+3)°, angle R=(2y+10)° and angle S=(4x-5)°,then find smallest angle ​

Answer»

is cyclic quadrilateralp + r = 180q + s = 180Now P + R = 1802x+4 + 2y + 10 = 1802(x+y) = 166x + y = 83.......(1) Now Q + S = 180y + 3 + 4x-5 = 1804x + y = 182.....(2) Subtracting (1) from (2) 4x+y-(x+y) = 182 - 833x = 99x = 33y = 83 - x = 83 - 33 = 50Now P = 2(33)+4 = 70Q = 50 + 3 = 53R = 2(50)+10 = 110S = 4(33)-5 = 127Hence Q is the smallest angleHope you gottaSahil Thakur



Discussion

No Comment Found

Related InterviewSolutions