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In a cyclotron, a magnetic filed of 3.5 Wb//m^(2) is used to accelerate protons. What should be the time interval in which the electric field between the dees should be reversed? [Mass of the proton =1.67 xx 10^(-27) kg, charge on the proton =1.6 xx 10^(-19)C] |
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Answer» Solution :Data: `B=3.5 Wb//m^(2), m=1.67 xx 10^(-27) kg, q=1.6 xx 10^(-19)` C, `T= (2pim)/(qB)` `therefore t=T/2 = (PIM)/(qB) = (3.142 xx 1.67 xx 10^(-27))/(3.5 xx 1.6 xx 10^(-19)) = 9.37 xx 10^(-9) s` This is the required time interval. |
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