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In a cyclotron, a magnetic induction of 1.4 T is used to accelerate protons. How rapidly should the electric field between the dees be reversed?(a) 5.2 × 10^-8 s(b) 2.34 × 10^-8 s(c) 792.25 × 10^-8 s(d) 46.25 × 10^-8 sI got this question in unit test.My question is from Motion in Combined Electric and Magnetic Field in section Moving Charges and Magnetism of Physics – Class 12

Answer»

The correct answer is (b) 2.34 × 10^-8 s

The best I can EXPLAIN: Time period, t = \(\FRAC {\pi m}{qB}\)

t = \(\frac {(3.14 \, \TIMES 1.67 \, \times \, 10^{-27})}{(1.6 \, \times \, 10^{-19} \, \times \, 1.4)}\)

t = 2.34 × 10^-8 s



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