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In a Δ ABC, if AB = BC = 120° and ∠B = 70°, Find ∠A. |
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Answer» Consider Δ ABC, We have, ∠B = 70° And, AB = AC Therefore, Δ ABC is an isosceles triangle. ∠B = ∠C (Angle opposite to equal sides are equal) ∠B = ∠C = 70° And ∠A + ∠B + ∠C = 180°(Angles of triangle) ∠A + 70° + 70° = 180° ∠A = 40° |
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