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In a ΔABC, it is given that AD is the internal bisector of ∠A. If BD = 4 cm, DC = 5 cm and AB = 6 cm, then AC = ? |
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Answer» ━━━━━━━━━━━━━━━━━━━━ ✤ Required Answer:✒ GiveN:
✒ To FIND:
━━━━━━━━━━━━━━━━━━━━ ✤ How to Solve?We can SEE here, that INTERNAL bisector of an Angle is given, and we have to find a side of the triangle. For this, LET's know about Internal angle bisector theoram. ➤ The internal angle bisector of an triangle from any vertex divides the opposite side in the ratio of the side containing the angle which was bisected. ✒ So, By using this theoram, let's solve the question. ━━━━━━━━━━━━━━━━━━━━ ✤ Solution:✒ REFER to the attachment... We have, the required bisected angle ∠A. Then, opposite side of ∠A is BC. According to theoram, ⇛ AB/AC = BD/DC We have,
By using the relation, ⇛ 6/x = 4/5 ⇛ x = 6×5 /4 cm ⇛ x = 7.5 cm ✒ Required Length of AC = 7.5 cm Hence, Solved !! ━━━━━━━━━━━━━━━━━━━━ |
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