In a ΔABC, obtuse angled at B, if AD is perpendicular to CB produce – InterviewSolution

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1.	In a ΔABC, obtuse angled at B, if AD is perpendicular to CB produced, prove that AC = AB2 + BC2 + 2BC × BD [4 MARKS]
Answer» In a ΔABC, obtuse angled at B, if AD is perpendicular to CB produced, prove that AC = ${A B}^{2}$ + ${B C}^{2}$ + 2BC $\times$ BD [4 MARKS]

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