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In a diffraction pattern due to a single slit of width a, the first minimum is observed at an angle 30^(@) when light of wavelength 5000 Å is incident on the slit. The first secondary maximum is observed at an angle of ... |
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Answer» `sin^(-1)((2)/(3))` `a sin THETA= lambda "" [ n=1]` `:. a sin 30^(@) = lambda` `:. a xx(1)/(2)= lambda` For first MAXIMUM, `a sin theta_(1)=(2n+)(lambda)/(2)` `:. a sin theta_(1)=(3lambda)/(2)` `:. sin theta_(1)=(3lambda)/(2)` `:. sin theta_(1)=(3)/(4)` `:. theta_(1)=sin^(-1)((3)/(4))` |
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