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In a diode, the change in voltage being applied across it is 2V. The change in minority carriers outside the depletion region is 1.2×10^-8. Find diffusion capacitance.(a) 6 pF(b) 6 μF(c) 1.2 nF(d) 6nFI had been asked this question during an internship interview.I need to ask this question from Diffusion Capacitance in portion Diode Circuit of Analog Circuits

Answer»

Correct option is (d) 6nF

Easy EXPLANATION: Diffusion capacitance = \(\frac{dQ}{dV}\)

CD = \(\frac{1.2 x 10^{-8}}{2}\)

CD = 6 NF.


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