1.

In a double slit experiment, at a certain point on the screen the path difference between the two interfering waves is 1/3 rdof a wavelength. The ratio of the intensity of light at that point to that at the centre of a bright fringe is:

Answer»

`0.25`
`0.67`
`0.75`
`0.56`

SOLUTION :`I=I_(0)cos^(2)((Deltaphi)/(2)),"""I/I_0=cos^2((Deltaphi)/(2))`
`I/I_0=cos^2(((2PI)/lamdaxxlamda/3)/2)`
`I/I_0=cos^(2)(pi/3), ""I/I_0=0.25`


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