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In a double slit experiment using monochromatic light, the fringe patern shifts by a certain distance on the screen when a mica sheet of mu= 1.6 and thickness t = 1.964 mu m is introduced in the path of the one of the interfering waves.The mica sheet is then removed and the distance between the slits and the screen is doubled.It is found that the distance between successive max. or min. is now the same as the observed fringe shift upon introducing of the mica sheet. Calculate the wavelength of light used in experiement: |
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Answer» `3246 Å` When D is DOUBLED, `beta = (lambda 2D)/(d)` Now FRINGE shift = fringe width, when D is doubled `therefore ((mu -1)t D)/(d) = (2 lambda D)/(d)` or `lambda = ((mu - 1)t)/(2) = 5892 Å`. |
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