In a ΔPQR, N is a point no PR, such that QN⊥PR.NR=QN2 , then prove – InterviewSolution

1.	In a ΔPQR, N is a point no PR, such that QN⊥PR.NR=QN2 , then prove that ∠PQR=90∘
Answer» In a $Δ$ PQR, N is a point no PR, such that $Q N ⊥ P R . N R = Q N^{2}$ , then prove that $∠ P Q R = 90^{\circ}$

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