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In a Duma's method 0.3g of an organic compound gave 50ml of nitrogen collected at 27^(@)C and 715mm pressure . The percentage of N is (aqueous tension at 27^(@)C=15mm) : |
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Answer» <P>`19.46%` `=700mm` To calculate the volume of `N_(2)` at S.T.P `{:(V_(1)=50mL,V_(2)=?),(p_(1)=700mm,p_(2)760MM),(T_(1)=300K,T_(2)=273K):}` Applying `(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))` or `V_(2)=(p_(1)V_(1)T_(2))/(p_(2)T_(1))` `:.V_(2)=(700xx50xx273)/(760xx300)` `=41.9mL` `22400mL` of nitrogen at S.T.P.weigh `=28g` `41.9mL` of nitrogen at S.T.P.weigh `=(28xx41.9)/(22400)` `=0.0524g` Percentage of nitrogen `=(0.0524)/(0.3)xx100=17.46%` |
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