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In a family of 10 members, 7 of them like tea or coffee, 4 of them like tea and 5 of them like coffee. How many of them like neither tea nor coffee?(a) 1(b) 2(c) 3(d) 4I have been asked this question in homework.This intriguing question originated from Practical Problems on Union and Intersection of Two Sets topic in section Sets of Mathematics – Class 11

Answer» CORRECT choice is (c) 3

For explanation I would say: GIVEN, N (T ∪ C) = 7.

By de Morgan’s law, n (T’ ∩ C’) = n (T ∪ C)’ = Total – n (T ∪ C) = 10 – 7 = 3.

So, 3 MEMBERS like neither tea nor coffee.


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