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In a first-order reaction, it takes the reactant 40.5 minutes to be 25% decomposed. Find the rate constant of the reaction. |
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Answer» Solution :SINCE the reactant is 25% DECOMPOSED in 40.5 min, the remaining reactants is `75%," i.e."(a-x)=0.75" at "40.5" min."` `k=(2.303)/(t)LOG""(a)/(a-x)=(2.303)/("40.5 min")log""(a)/(0.75a)` `=0.05686log" 1.33 min"^(-1)` `=0.05686xx0.1249" min"^(-1)` `=7.1xx10^(-3)" min"^(-1)` |
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