1.

In a first order reaction the concentration of the reactant decreases from 800 mol/ dm^(3) to 50 mol/ dm^(3) in 2xx10^(4) sec . The rate constant of the reaction in sec^(-1) is :

Answer»

`2XX10^(4)`
`3.45xx10^(-5)`
`1.386xx10^(-4)`
`2xx10^(-4)`

Solution :(C ) k = `(2.303)/(t) "log" ([A]_(0))/([A])`
`k = (2.303)/(2xx10^(4))"log" (800)/(50) = 1.38 xx10^(-4) s^(-1)`


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