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In a first order reaction, the concentration of the reactant is reduced from 0.6 mol L^(-1) to 0.2 mol L^(-1) in 5 minutes. Calculate the rate constant of the reaction. |
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Answer» Solution :Substituting the values in the first ORDER EQUATION `k=(2.303)/(t)"LOG"([R]_(0))/([R])` `k=(2.303)/(5"MIN")xx"log"(0.6)/(0.2) or k=(2.303)/(5)xx log3` or `k=(2.303)/(5)xx0.4771=0.2198` |
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