1.

In a first order reaction , the concentration of the reactant is reduced to 1/8 of the initial concentration in 75 minutes at 298 K . What is the half-life period of the reaction in minutes

Answer»

50
15
45
25

Solution :Let a = 1 , a-x = 1/8 , t = 75 min
For first order reaction
`k = (2.303)/(t)` LOG `(a)/(a-x)`
`k = (2.303)/(75)` log `(1)/(1//8) = (2.303 xx 0.903)/(75) "min"^(-1)`
For first order reaction
`t_(1//2) = (0.693)/(k) = (0.693 xx 75)/(2.303 xx 0.903) = 25` min .


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