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In a fraction, if unity is added to the numerator and subtracted from the denominator, it becomes `(2)/(3)`. Instead, if unity is subtracted from the numerator and added to the denominator, it becomes `(1)/(2)`. Find the fraction. |
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Answer» Let the fraction be `(x)/(y)`, applying the first conditions, we get, `(x +1)/(y-1) = (2)/(3)` `rArr 3x + 3 = 2y -2` `rArr 3x - 2y = -5` (1) Applying the second conditions, we get, `(x-1)/(y +1) = (1)/(2)` `rArr 2x -3 = 2y +1` `rArr 2x - y = 3` (2) By solving the Eqs. (1) and (2) using any of the methods discussed earlier, we get x = 11 and y = 19 `:.` The fraction is `(11)/(19)` |
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