1.

In a frequency distribution, the mid value of the class is 10 and width of the class is 6. Find the lower limit of the class.

Answer»

Consider the lower limit of the class as a

So the upper limit can be written as a + 6

We get

(a + (a + 6))/ 2 = 10

By cross multiplication

2a + 6 = 20

On further calculation

2a = 14

By division

a = 7

Class width = 6
Mid value = 10 cm

Half of Class width =
= 3

Lower limit of a class = Mid value - half of class width
= 10 - 3
= 7
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If you were asked to find the upper limit of the class , then ,

Upper limit = Mid value + half of class width
= 10 + 3
= 13


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